Australian (ASX) Stock Market Forum

The number game

Ok, new pattern...

86.5,
115 1/3,
259.5,
230 2/3,
432.5,
346,
605.5,
461 1/3... what are the next 2 numbers, you wont find the answer for this one on google :p:
Are the next numbers 778.5, 576 2/3, 951.5 & 692?
 
wow... how did you work that one out??
*yes, it was right

After messing about with the numbers unsuccessfully for a while, I plotted the points on a chart and the pattern became pretty clear. Then it was just a matter of using regresison to work out the variables.
 
How d u get to this polynomial

? (unless you made the q but in general how do u form the pnomial)

Yea, i made the question.. so i know the polynomial form of it :p

578 1512.5 3960.5 10368 27144.5

wow, you are pretty good... how did you get this one? I'm sure the pattern isn't that obvious when plotted on a graph. I even took out the first number to make it look less like a Fibonacci sequence :(
 
wow, you are pretty good... how did you get this one? I'm sure the pattern isn't that obvious when plotted on a graph. I even took out the first number to make it look less like a Fibonacci sequence :(
A large amount of it was luck to be honest. It was the type of thing I could of looked at for hours and not realised, but as it happens, it took about 2 mins.

Plotting it on the chart, it looked to be in the form of of either e(x) or x^2.
The next clue was the occasion .5. Thinking that you're likely to get one from time to time if you divide a series of numbers by 2 and some happen to be odd, I multiplied everything by 2. From there it was pretty obvious they were fib^2...
 
A large amount of it was luck to be honest. It was the type of thing I could of looked at for hours and not realised, but as it happens, it took about 2 mins.

Plotting it on the chart, it looked to be in the form of of either e(x) or x^2.
The next clue was the occasion .5. Thinking that you're likely to get one from time to time if you divide a series of numbers by 2 and some happen to be odd, I multiplied everything by 2. From there it was pretty obvious they were fib^2...

genius much?
 
can anyone explain how to for example get the 100th number

given a series , i understand that you have to derive a polynomial

of some sort. But how to do this?
 
can anyone explain how to for example get the 100th number

given a series , i understand that you have to derive a polynomial

of some sort. But how to do this?

you could plot the points on a graph to help find the polynomial...
 
How about this

31

239

1007

6935

14051

25639

100 th number anyone?
or maybe just the next 3
 
Its a polynomial to the power of 5 or higher... i cant be bothered to work it out
I think it's a polynomial to the power 6 or higher. Given we have only 6 data points, impossible to predict future points exactly. Can estimate though...
 
Its actually polynomial of degree 4

there for 6 is enough

first time making a sequence

so just tell how many more i need to give

the pnomial was

10x^4+3x^3+12x^2+x+5
 
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