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1 to D1
T to B4
2 to A1
3 to B1
T to D4
Yep. Well done.
1 to D1
T to B4
2 to A1
3 to B1
T to D4
Yep. Well done.
Correct me if mistaken, but there appears to be several solutions to this one.
Move 3 could be 2 to A2 or A3
Then move 4 could be 3 to A1 or A2
Wimbledon
Q1: 127 = 64+32+16+8+4+2+1, or 128-1
Q2: 24 = 4 aces or 4 lethal first returns per game * 6 games per set
Retraction. The answer to part 2 is once. You only need to hit the ball once to win a set. This is the explanation (BTW, I thought 12 too):
Imagine if every time you serve you swing at the ball and miss. This is a fault. Do this twice in a row and you lose the point. Do it eight times in a row and you lose the game.
Now imagine you do this for your six service games and that your opponent also double faults on every serve. The score after 12 games will be 6-6 and the set will enter the tiebreak.
If you continue to swing at the ball and miss, and your opponent double faults, neither of you will be able to win the tie-break. But depending on who serves first you will either get to 6-5, or 7-6 ahead. When you you do, ace that serve and you will have won the set with your racket hitting the ball only once.
Oh Em Gee :1zhelp: That would be some match to watch (not!)
One prisoner always predicts the opposite of his flip. The other prisoner always predicts the exact result of his flip. They both continue to live.
8 cm - correct
Forty third - wrong
Forty sixth
Correct
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