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ASF Spoilers Thread

Correct me if mistaken, but there appears to be several solutions to this one.

Move 3 could be 2 to A2 or A3

Then move 4 could be 3 to A1 or A2

Yes, there is. Moves 1 and 2 are key. Then its just a matter of getting pieces 2 and 3 anywhere out of the way so that T can be slid down.
 
1 to D1
T to the right
2 to A3
3 to A2
T down into the corner
 
Wimbledon
Q1: 127 = 64+32+16+8+4+2+1, or 128-1
Q2: 24 = 4 aces or 4 lethal first returns per game * 6 games per set
 
Wimbledon
Q1: 127 = 64+32+16+8+4+2+1, or 128-1
Q2: 24 = 4 aces or 4 lethal first returns per game * 6 games per set

Correction: Q2 needs only 12 if the opponent double-faults his/her 12 serves :banghead:

hat-tip to cynic :)
 
Cynic takes the winnings and the extra points..

You are both correct on the first. 127 matches. Because it is a knockout, each participant must lose 1 match, except the final winner. Hence 127 matches lost or as Cynic put it (128-1). That was the easier way to solve this problem.

12 is the answer to part 2. Although it takes you a minimum of 4 hits to win a game, you only need to hit the ball in the 3 games you serve, thus 12 hits. Your opponent can double fault every point of the 3 games he serves without you needing to hit the ball.

PS. Pixel, our posts crossed
 
Retraction. The answer to part 2 is once. You only need to hit the ball once to win a set. This is the explanation (BTW, I thought 12 too):

Imagine if every time you serve you swing at the ball and miss. This is a fault. Do this twice in a row and you lose the point. Do it eight times in a row and you lose the game.

Now imagine you do this for your six service games and that your opponent also double faults on every serve. The score after 12 games will be 6-6 and the set will enter the tiebreak.

If you continue to swing at the ball and miss, and your opponent double faults, neither of you will be able to win the tie-break. But depending on who serves first you will either get to 6-5, or 7-6 ahead. When you you do, ace that serve and you will have won the set with your racket hitting the ball only once.
 
Retraction. The answer to part 2 is once. You only need to hit the ball once to win a set. This is the explanation (BTW, I thought 12 too):

Imagine if every time you serve you swing at the ball and miss. This is a fault. Do this twice in a row and you lose the point. Do it eight times in a row and you lose the game.

Now imagine you do this for your six service games and that your opponent also double faults on every serve. The score after 12 games will be 6-6 and the set will enter the tiebreak.

If you continue to swing at the ball and miss, and your opponent double faults, neither of you will be able to win the tie-break. But depending on who serves first you will either get to 6-5, or 7-6 ahead. When you you do, ace that serve and you will have won the set with your racket hitting the ball only once.

Oh Em Gee :1zhelp: That would be some match to watch (not!)
Would either player have made it to Wimbledon though? :confused:
 
Well it was a nice illusion whilst it lasted, but then I never was very good at tennis.
 
One prisoner always predicts the opposite of his flip. The other prisoner always predicts the exact result of his flip. They both continue to live.
 
1) 8cm (2 covers plus the full width of volume II)
2: forty sixth (ignoring [...], the 2nd c is in "sentence", being the 36th letter, plus 10 letters for the number spelled in full)
 
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